wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Statement 1: Period of sin3x+cos3x is 2π
Statement 2: Period of sin(xn) is 4πn=2

A
only I is true
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
only II is true
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Both I and II are true
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Neither I nor II true
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B Both I and II are true
We've the period of the functions sinx and cosx is 2π.
Also the period of the function sin3x and cos3x is 2π.
And hence the period of the function sin3x+cos3x is 2π.
So statement-I is true.
Now the period of the function sinxn is 2πn.
According to the problem we have,
2πn=4π
Or, n=2.
So statement-II is also true.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Derivative of Standard Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon