Statement 1: Reduction of but-2-yne by $N a / l i q . N H_{3}$ gives trans but-2-ene.
Statement 2: It is an example of anti-addition.

Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Statement-1 is true, statement-2 is true, statement-2 is not a correct explanation for statement-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-1 is true, statement-2 is false

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement-1 is false, statement-2 is true

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1
This is an example of anti addition to preferentially obtain a trans alkene.

Thus, when 2-butyne is reduced with sodium in liq ammonia, trans-2-butene is obtained. The triple bond is selectively reduced to double bond.

Thus, both the statements are correct and the statement 2 is the correct explanation of statement 1.

Suggest Corrections

Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

\sim (p \leftrightarrow\sim q)

p \leftrightarrow q

\sim (p \leftrightarrow\sim q)

Join BYJU'S Learning Program