STATEMENT-1 : Sucrose is a reducing sugar.
STATEMENT-2 : In sucrose glucose unit has pyranose form and fructose unit has furanose form.

STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1

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STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation for STATEMENT-1

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STATEMENT-1 is True, STATEMENT-2 is False

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STATEMENT-1 is False, STATEMENT-2 is True

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Solution

The correct option is D STATEMENT-1 is False, STATEMENT-2 is True
Both the free carbonyl groups in sucrose are involved in the glycosidic linkage formation. So, it is a non reducing sugar due to absence of free carbonyl group. So, assertion is false.
In sucrose, the glucose unit is in the 6 membered pyranose form and the fructose unit is in the 5 membered furanose form. So, reason is correct.

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