Statement 1: The electrostatic force between the plates of a charged isolated capacitor decreases when dielectric fills whole space between plates.
Statement 2: The electric field between the plates of a charged isolated capacitance decreases when dielectric fills whole space between plates

Statement-1 is true, Statement-2 is true and Statement-2 is the correct explanation for Statement-1

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Statement-1 is true, Statement-2 is true and Statement-2 is NOT the correct explanation for Statement-1

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Statement-1 is true, Statement-2 is false

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Statement-1 is false, Statement-2 is true

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Solution

The correct option is D Statement-1 is true, Statement-2 is true and Statement-2 is the correct explanation for Statement-1
For isolated capacitor the charge (Q) remains constant.
The field between the plates without dielectric is $E = \frac{Q}{A ϵ_{0}}$
The field between the plates with dielectric is $E^{'} = \frac{Q}{A k ϵ_{0}} = E / k$ where k is dielectric constant. Thus the filed between the plates will decrease.
The force between the plates do not depend on the field between the plates and its depend on the filed due to a charge plate.

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Statement 1: The electrostatic force between the plates of a charged isolated capacitor decreases when dielectric fills whole space between plates.Statement 2: The electric field between the plates of a charged isolated capacitance decreases when dielectric fills whole space between plates

Statement 1: The electrostatic force between the plates of a charged isolated capacitor decreases when dielectric fills whole space between plates.
Statement 2: The electric field between the plates of a charged isolated capacitance decreases when dielectric fills whole space between plates