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Question
Statement 1-The graph between velocity v/s displacement of a praticle in a Rectilinear motion for which velocity is directly proportional to net force applied is a straight line
Statement 2- the velocity-displacement graph is straight line if slope of accelaration-time is zero.
A.Statement 1 and Statement 2 is true.Statement-2 is correct explanation for statement-1.
B.Statement 1 and Statement 2 is true.Statement-2 is not correct explanation for statement-1.
C.Statement 1 is false and Statement 2 is true.
D.Statement 1 is true and Statement 2 is false.
Statement 1-The graph between velocity v/s displacement of a praticle in a Rectilinear motion for which velocity is directly proportional to net force applied is a straight line
Statement 2- the velocity-displacement graph is straight line if slope of accelaration-time is zero.
A.Statement 1 and Statement 2 is true.Statement-2 is correct explanation for statement-1.
B.Statement 1 and Statement 2 is true.Statement-2 is not correct explanation for statement-1.
C.Statement 1 is false and Statement 2 is true.
D.Statement 1 is true and Statement 2 is false.
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Solution
Dear student,
the correct option is D.
The first statement is right. When velocity(v) is proportional to force, it means v is proportional to acceleration (a) assuming mass remains constant.
a~v(~ is used to show proportionality)
a=kv, where k is a constant.
Therefore, a/v=k
Slope of velocity displacement graph is dv/ds
dv/ds= dv/dt×dt/ds=a/v=k
i.e., the slope is a constant. hence it is a line. so first statement is true.
Now the second statement:
Slope of acceleration time graph=da/dt=0
i.e., acceleration is a constant.
Now slope of velocity displacement graph is dv/ds
dv/ds=dv/dt×dt/ds= a/v.
This is not a constant as v is a variable, even when a is constant. Thus the statement is wrong Thank you
the correct option is D.
The first statement is right. When velocity(v) is proportional to force, it means v is proportional to acceleration (a) assuming mass remains constant.
a~v(~ is used to show proportionality)
a=kv, where k is a constant.
Therefore, a/v=k
Slope of velocity displacement graph is dv/ds
dv/ds= dv/dt×dt/ds=a/v=k
i.e., the slope is a constant. hence it is a line. so first statement is true.
Now the second statement:
Slope of acceleration time graph=da/dt=0
i.e., acceleration is a constant.
Now slope of velocity displacement graph is dv/ds
dv/ds=dv/dt×dt/ds= a/v.
This is not a constant as v is a variable, even when a is constant. Thus the statement is wrong
Thank you
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