Statement 1 : The graph of a linear equation is a straight line.

Statement 2 : The solution of a pair of linear equations is a point common to two lines.

S1 is true but S2 is false

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S1 is false but S2 is true

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S1 and S2 are true

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S1 and S2 are false

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Solution

The correct option is C
S1 and S2 are true

The graph of linear equation is a straight line. A solution of a pair of linear equations is a point that satisfies both the equations.

Hence both the statements are true

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Similar questions

We are given the equation $x + 2 y = 3$

Statement 1: The degree of the equation is one.

Statement 2 : It is a linear equation in two variable.

The graph for the following system of equations :

$2 x + 3 y = 5 a n d 6 x + 9 y = 40$ is shown

S1: $\frac{a_{1}}{a_{2}}$ = $\frac{b_{1}}{b_{2}}$ ≠ $\frac{c_{1}}{c_{2}}$

S2 : The two lines intersect each other.

The solution for the equations $c_{1}$ x + $b_{1}$ y + $a_{1}$ = 0 and $c_{2}$ x + $b_{2}$ y + $a_{2}$ = 0 is

$S_{1}$ : x = $\frac{(b_{1} a_{2} - b_{2} a_{1})}{(c_{1} b_{2} - c_{2} b_{1})}$

$S_{2}$ : y = $\frac{(c_{1} a_{2} - c_{2} a_{1})}{(a_{1} b_{2} - a_{2} b_{1})}$

In the given figure, ABCD is a parallelogram and PD is parallel to QC.

S1 : $△$ APD $≅$ $△$ BQC

S2 : ar( $△$ APD) + ar(PBCD) = ar( $△$ BQC) + ar(CDPB)

The figure shows a parallelogram $P Q R S,$ in which, $A$ is the mid point of $P Q$ and $B$ is the mid point of $R S .$

Statement 1: $S X = X Y$

Statement 2: $X Y = Q Y$

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