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STATEMENT - 1 : The opposite side of a quadrilateral circumscribing a circle subtend supplementary angle at the centre of the circle.
STATEMENT - 2 : The angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line segment joining the points of contact at the centre.

A
Statement - 1 is True, Statement - 2 is True, Statement - 2 is a correct explanation for Statement - 1
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B
Statement - 1 is True, Statement - 2 is True : Statement 2 is NOT a correct explanation for Statement - 1
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C
Statement - 1 is True, Statement - 2 is False
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D
Statement - 1 is False, Statement - 2 is True
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Solution

The correct option is B Statement - 1 is True, Statement - 2 is True : Statement 2 is NOT a correct explanation for Statement - 1
Statement 1 is correct:
Join the vertices of the quadrilateral ABCD to the center of the circle.
In OAP and OAS,
AP=AS (Tangents from the same point)
OP=OS (Radii of the circle)
OA=OA (Common side)
OAP=OAS (SSS congruence condition)
POA=AOS

1=8
Similarly we get,
2=3
4=5
6=7

Adding all these angles,
1+2+3+4+5+6+7+8=360
(1+8)+(2+3)+(4+5)+(6+7)=360
21+22+25+26=360
2(1+2)+2(5+6)=360
(1+2)+(5+6)=180
AOB+COD=180
Similarly, we can prove that BOC+DOA=180
Hence, opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.

Statement 2 is correct as in quadrilateral DSRO, S=R=90 and as DS=DR, OS=OR, SDO=RDO and SOD=ROD and also SDR+SOR=180
Hence, statement 2 is also correct
But, it is not the correct explanation of statement 1 as the supplementary nature of tangent's angles does not relate to the angle subtended by the opposite sides at the center.

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