The correct option is
D Statement-
1 is false, statement-
2 is true
- Line =(2,1,−2)+t(2,6,−3)
Vector to line from point
=(1+2t,−3+6t,−3t)(1+2t,−3+6t,−3t)⋅(2,6,−3)=02+4t−18+36t+9t=0t=1649Length
=√(1+2t)2+(6t−3)2+(−3t)2
=√49t2−32t+10
=√(16)249−−32×1649+10
=17(√490−162)
=3√267
(Alternate Method) :-
We know that, the perpendicular distance of point P from the line joining A and B is |¯¯¯¯¯¯¯¯APׯ¯¯¯¯¯¯¯AB||¯¯¯¯¯¯¯¯AB|
Here, P=(1,4,−2), A=(2,1,−2) and B=(0,−5,1)
¯¯¯¯¯¯¯¯AP=P−A=(−1,3,0) and ¯¯¯¯¯¯¯¯AB=B−A=(−2,−6,3)
Then, |¯¯¯¯¯¯¯¯APׯ¯¯¯¯¯¯¯AB||¯¯¯¯¯¯¯¯AB|=|(−1,3,0)×(−2,−6,3)||(−2,−6,3)|
=|(9,3,12)|√4+36+9=√81+9+144√49=√2347=3√267
Hence, Statement-1 is false and Statement 2 is true.