wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

STATEMENT - 1: The slant height of frustum of a cone is 4 cm. and perimeters of its circular ends are 18 cm. and 6 cm. then the curved surface area is 48 sq. cm.
STATEMENT - 2: Curved surface area of frustum =π(r1+r2), where r1 and r2 are radii of the frustum and l is a slant height.

A
Statement - 1 is True, Statement - 2 is True, Statement - 2 is a correct explanation for Statement - 1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Statement - 1 is True, Statement - 2 is True : Statement 2 is NOT a correct explanation for Statement - 1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Statement - 1 is True, Statement - 2 is False
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Statement - 1 is False, Statement - 2 is True
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Statement - 1 is True, Statement - 2 is True, Statement - 2 is a correct explanation for Statement - 1
Curved surface area offrustum =π(r1+r2)l, where r1
and r2 are radii of frustum and l is a slant height
=227(9π+3π)×4=227×π(9+3)×4
=227×722(12)×4=48cm2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Combination of Solids
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon