wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Statement-1 : the two vectors a=1i+Pj+2k and b=3i+3j+Qk are parallel only if P=1 and Q+6.
Statement-2 : if two vectors a=a1i+a2j+a3k and b=b1i+b2j+b3k are parallel then a1a2=b1b2

A
Both statements are true and Statement-2 is correct explanation of Statement-1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both statements are true and Statement-2 is not correct explanation of Statement-1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Statement-2 is false but other is true
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Statement-1 is false but other is true
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Statement-2 is false but other is true
Two vectors a=a1i+a2j+a3k and b=b1i+b2j+b3k are parallel if and only if a1b1=a2b2=a3b3
a1a2=b1b2
So second statement is correct
In statement one , the vectors are a=1i+Pj+2k and b=3i+3j+Qk are parallel if and only if 13=P3=2Q
P=1 and Q=6
So statement one is wrong
Therefore option C is correct

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Applications of Cross Product
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon