Statement -1: Total number of moles in a closed system at new equilibrium is less than the old equilibrium if some amount of a substance is removed from a system (consider a reaction $A (g) ⇌ B (g))$ at equillibrium.
Statement -2: Equilibrium constant of the reaction is changed by removing some amount of a substance at equilibrium.

Statement-1 is true, Statement -2 is true and Statement-2 is correct explanation for Statement-1

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Statement-1 is true, Statement-2 is true and Statement -2 is NOT the correct explanation for Statement-1

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Statement-1 is false, Statement-2 is true

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Statement-1 is true, Statement-2 is false

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Solution

The correct option is D Statement-1 is true, Statement-2 is false
When some amount of the substance is removed, the total number of moles decreases as the mass decreases. But the relative concentrations of products and reactants will remain same so that the value of the equilibrium constant is not affected.

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Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

2 m g

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

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