Statement 1: When a man is standing on a stationary horizontal surface, the normal force exerted by the ground on him is equal and opposite to his weight.
Statement 2: According to Newton's $3^{r d}$ law , every action has an equal and opposite reaction.

Statement 1 - is true, statement- 2 is true and statement-2 is correct explanation for statement-1

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Statement 1 - is true, statement- 2 is true and statement-2 is NOT the correct explanation for statement-1

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Statement 1 - is true, statement- 2 is false

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Statement 1 - is false, statement- 2 is true

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Solution

The correct option is A Statement 1 - is true, statement- 2 is true and statement-2 is NOT the correct explanation for statement-1
The gravitational force and the normal force both act on the man and in Newton's third law the force pair of action-reaction is acting on different bodies. However, statement one is true, as the forces acting on the man balances itself. However, the reason is not the correct explanation.
Ans: (B)

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Similar questions

- 1 :

0 < x < y \Rightarrow {log}_{a} x > {log}_{a} y

a > 1

- 2 :

a > 1, {log}_{a} x

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} = (n + 2) 2^{n - 1} .

\sum_{r = 0}^{n} (r + 1)^{n} C_{r} x^{r} = (1 + x)^{n} + n x (1 + x)^{n - 1} .

n \geq 2,

\frac{1}{\sqrt{1}} + \frac{1}{\sqrt{2}} + . . . + \frac{1}{\sqrt{n}} > \sqrt{n}

\sqrt{n (n + 1)} < n + 1

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