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Valency and Oxidation States

Statement 1...

Question

Statement $1$ : When a piece of $A l$ is dropped into a $1 M$ solution of $M g C l_{2}$ , element $M g$ appears.
Statement $2$ : $A l$ is more readily oxidized than $M g$ .

Statement

1

and Statement

2

are correct and Statement 2 is the correct explanation of Statement

1

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Both the Statement

1

and Statement

2

are correct, but Statement

2

is NOT the correct explanation of Statement

1

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Statement

1

is correct, but Statement

2

is not correct

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Both Statement

1

and Statement

2

are not correct.

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Solution

The correct option is D Both Statement $1$ and Statement $2$ are not correct.
$3 M g {C l}_{2} + 2 A l ⟶ 2 {A l C l}_{3} + 3 M g$ (wrong)
$E^{o} {M g}^{2 +} / M g = - 2.37 V$ (more $- v e$ )
$E^{o} {A l}^{3 +} / A l = - 1.66 V$
$E^{o} {M g}^{2 +} / M g$ is more $- v e$ $∴$ oxidation reduction should occur in this case.
$3 M g + 2 {A l C l}_{3} ⟶ 2 A l + 3 M g {C l}_{2}$ (right)

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Statement 1: When a piece of Al is dropped into a 1 M solution of MgCl2, element Mg appears.Statement 2: Al is more readily oxidized than Mg.

The correct option is D Both Statement 1 and Statement 2 are not correct.3MgCl2+2Al⟶2AlCl3+3Mg (wrong)EoMg2+/Mg=−2.37V (more −ve)EoAl3+/Al=−1.66VEoMg2+/Mg is more −ve ∴ oxidation reduction should occur in this case.3Mg+2AlCl3⟶2Al+3MgCl2 (right)

Statement $1$ : When a piece of $A l$ is dropped into a $1 M$ solution of $M g C l_{2}$ , element $M g$ appears.
Statement $2$ : $A l$ is more readily oxidized than $M g$ .