statement 1: When a tiny circular obstacle is placed in the path of light from some distance, a bright spot is seen at the center of the shadow of the obstacle.
statement 2: Destructive interference occurs at the center of the shadow.

If both statement 1 and statement 2 are true but statement 2 is the correct explanation of statement 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

If both statement 1 and statement 2 are true but the reason is not the correct explanation of statement 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

If statement 1 is true but statement 2 is false

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

If both the statement 1 and statement 2 are false

No worries! We‘ve got your back. Try BYJU‘S free classes today!

If statement 2 is true but statement 1 is false

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C If statement 1 is true but statement 2 is false
A bright spot is found at the centre of circular fringe patterns formed due to diffraction of light at the edge of circular obstacles. This bright spot is due to constructive interference there by secondary wavelets.

Suggest Corrections

Similar questions

C - O

C - O

Choose the correct option.

Statement $1 : (p \land \sim q) \land (\sim p \land q)$ is a fallacy.

Statement $2 : (p \Rightarrow q) \Leftrightarrow (\sim q \Rightarrow\sim p)$ is a tautology.

x^{5} + 2 x^{4} + 3 x^{3} + x^{2} - 7 x + 8

x^{5} + 2 x^{4} + 3 x^{3} + x^{2} - 7 x + 8

Statement 1: A polynomial P(x) of degree greater than or equal to one, when divided by x – a, leaves a remainder zero.

Statement 2: x – a is a factor of the polynomial P(x).

1 :

x y + y z + z x = 1

x, y, z \in R^{+}

\frac{x}{1 + x^{2}} + \frac{y}{1 + y^{2}} + \frac{z}{1 + z^{2}} = \frac{2}{\sqrt{(1 + x^{2}) (1 + y^{2}) (1 + z^{2})}}

2 :

A B C

sin 2 A + sin 2 B + sin 2 C = 4 sin A sin B sin C

Join BYJU'S Learning Program