CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Statement-1 : When ultraviolet light is incident on a photocell, its stopping potential is v0 and the maximum kinetic energy of the photo electrons is Kmax . When the ultraviolet light is replaced by X-rays, Kmaxincreases but v0 , decreases.
Statement -2: Photo electrons are emitted with speeds ranging from zero to a maximum value.Below a certain negative voltage V0 ,no photons are emitted in a photocell

A
Statement-1 is True,statement-2 is True;Statement-2 is correct explanation for statement-1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Statement-1 is True,Statement-2 is True; Statement-2 is NOT a correct explanation for statement-1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Statement-1 is True,Statement-2 is False
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Statement-1 is False, Statement-2 is True
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Statement-1 is False, Statement-2 is True
The stopping potential is independent of its intensity. If q is the charge on the electron and v0 is the stopping potential, then Kmax=qv0. so asKmax increases v0 also increases when X-ray applied because the stopping potential is independent of its intensity. so statement 1 is false.
Generally,photo electrons are emitted with speeds ranging from zero to a maximum value and some there cut off voltage to emit photon. so statement 2 is true.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
I vs V - Varying Frequency
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon