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Standard XII

Chemistry

Shapes of Orbitals and Nodes

Statement: Al...

Question

Statement: All $s$ -orbitals in the $H$ -atom corresponds to a non-zero probability density at the nucleus.
Explanation: The probability density is given by: $ψ^{2}$ and $ψ \propto e^{- Z r / 2 a_{0}}$

Both Statement and Explanation are correct and Explanation is the correct explanation for the statement

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Both Statement and Explanation are correct but Explanation is not the correct explanation for the statement

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Statement is correct but Explanation is wrong

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Statement is wrong but Explanation is correct

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Solution

The correct option is C Statement is correct but Explanation is wrong
$ψ_{n s}$ orbital is proportional to:
(1) a polynomial in 'r' with $n - 1$ roots
(2) $e^{\frac{- Z r}{n a_{o}}}$
Neither polynomial nor exponential part becomes zero at r = 0.
Hence, $ψ_{n s} \neq 0$ at r = 0

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Shapes of Orbitals and Nodes

Standard XII Chemistry

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Statement: All s-orbitals in the H-atom corresponds to a non-zero probability density at the nucleus. Explanation: The probability density is given by: ψ2 and ψ∝e−Zr/2a0

The correct option is C Statement is correct but Explanation is wrongψns orbital is proportional to: (1) a polynomial in 'r' with n−1 roots (2) e−Zrnao Neither polynomial nor exponential part becomes zero at r = 0. Hence, ψns≠0 at r = 0

Statement: All $s$ -orbitals in the $H$ -atom corresponds to a non-zero probability density at the nucleus.
Explanation: The probability density is given by: $ψ^{2}$ and $ψ \propto e^{- Z r / 2 a_{0}}$

The correct option is C Statement is correct but Explanation is wrong
$ψ_{n s}$ orbital is proportional to:
(1) a polynomial in 'r' with $n - 1$ roots
(2) $e^{\frac{- Z r}{n a_{o}}}$
Neither polynomial nor exponential part becomes zero at r = 0.
Hence, $ψ_{n s} \neq 0$ at r = 0