You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Shapes of Orbitals and Nodes

Statement: Al...

Question

Statement: All $s$ -orbitals in the $H$ -atom corresponds to a non-zero probability density at the nucleus.
Explanation: The probability density is given by: $ψ^{2}$ and $ψ \propto e^{- Z r / 2 a_{0}}$

Both Statement and Explanation are correct and Explanation is the correct explanation for the statement

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Both Statement and Explanation are correct but Explanation is not the correct explanation for the statement

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Statement is correct but Explanation is wrong

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Statement is wrong but Explanation is correct

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C Statement is correct but Explanation is wrong
$ψ_{n s}$ orbital is proportional to:
(1) a polynomial in 'r' with $n - 1$ roots
(2) $e^{\frac{- Z r}{n a_{o}}}$
Neither polynomial nor exponential part becomes zero at r = 0.
Hence, $ψ_{n s} \neq 0$ at r = 0

Suggest Corrections

Similar questions

Given below a statement (S) and explanation (E) is given. Choose the appropriate answer:

Statement (S): $O_{2}$ is diamagnetic

Explanation (E): $O_{2}$ has two electrons in anti-bonding $π$ orbitals.

Q. Choose the correct option based on the statements given:

Statement 1: Carbon always share electrons to form a covalent bond with other elements.

Statement 2:

C^{4 +}

and

C^{4 -}

ions are highly unstable.

Choose the correct option based on the statements given below:

Statement 1: Carbon always shares electrons or forms a covalent bond with other elements.

Statement 2: $C^{4 +}$ and $C^{4 -}$ ions are highly unstable.

Assertion (A) Boiling points of alcohols and ethers are high.
Reason (R) They can form intermolecular hydrogen-bonding.
(a) Assertion and reason both are correct and reason is correct explanation of assertion.
(b) Assertion and reason both are wrong statements.
(c) Assertion is correct statement but reason is wrong statement.
(d) Assertion is wrong statement but reason is correct statement.
(e) Both assertion and reason are correct statements but reason is not correct explanation of assertion.

Assertion (A) Bond angle in ethers is slightly less than the tetrahedral angle.
Reason (R) There is a repulsion between the two bulky (- R) groups.
(a) Assertion and reason both are correct and reason is correct explanation of assertion.
(b) Assertion and reason both are wrong statements.
(c) Assertion is correct statement but reason is wrong statement.
(d) Assertion is wrong statement but reason is correct statement.
(e) Both assertion and reason are correct statements but reason is not correct explanation of assertion.

Join BYJU'S Learning Program

Explore more

Shapes of Orbitals and Nodes

Standard XII Chemistry

Join BYJU'S Learning Program

Statement: All s-orbitals in the H-atom corresponds to a non-zero probability density at the nucleus. Explanation: The probability density is given by: ψ2 and ψ∝e−Zr/2a0

The correct option is C Statement is correct but Explanation is wrongψns orbital is proportional to: (1) a polynomial in 'r' with n−1 roots (2) e−Zrnao Neither polynomial nor exponential part becomes zero at r = 0. Hence, ψns≠0 at r = 0

Statement: All $s$ -orbitals in the $H$ -atom corresponds to a non-zero probability density at the nucleus.
Explanation: The probability density is given by: $ψ^{2}$ and $ψ \propto e^{- Z r / 2 a_{0}}$

The correct option is C Statement is correct but Explanation is wrong
$ψ_{n s}$ orbital is proportional to:
(1) a polynomial in 'r' with $n - 1$ roots
(2) $e^{\frac{- Z r}{n a_{o}}}$
Neither polynomial nor exponential part becomes zero at r = 0.
Hence, $ψ_{n s} \neq 0$ at r = 0