Question

Statement: All $s$-orbitals in the $H$-atom corresponds to a non-zero probability density at the nucleus.
Explanation: The probability density is given by: ${\psi }^2$ and $\psi \propto e^{-Zr/2a_0}$

• A. Both Statement and Explanation are correct and Explanation is the correct explanation for the statement
• B. Both Statement and Explanation are correct but Explanation is not the correct explanation for the statement
• C. Statement is correct but Explanation is wrong
• D. Statement is wrong but Explanation is correct

Answer 1

The correct option is C Statement is correct but Explanation is wrong

${\psi }_{ns}$ orbital is proportional to:
(1) a polynomial in 'r' with $n-1$ roots
(2) $e^{\frac{-Zr}{n{a}_o}}$
Neither polynomial nor exponential part becomes zero at r = 0.
Hence, ${\psi }_{ns}\ne 0$ at r = 0