Question

Statement: Barium sulphate is sparingly soluble in water whereas beryllium sulphate is freely soluble.

Enter 1 if the given statement is true if false enter 0

Answer 1

$\begin{array}{cc}BaS{O}_4\left(Bariumsulphate\right)& BeS{O}_4\\ H.E<L.E& H.E>L.E\end{array}$

Hydration energy of barium sulphate is less than its lattice energy and hydration energy of beryllium sulphate is more than its lattice energy. Therefore, barium sulphate is insoluble and beryllium sulphate is freely soluble.

Hence, the given statement is $\text{false}$ and correct entry is $0$