Question

Statement : $\left[Ni{\left(CO\right)}_4\right]$ and $[Ni\left(CO\right){}_4{]}^{-2}$ both are tetrahedral in shape.

State whether the statement is True or False?

• A. True
• B. False

Answer 1

The correct option is B False

$\left[Ni\right(CO{)}_4]$ i.e. Nickel tetra carbonyl has a hybridisation of $s{p}^3$ and therefore its geometry is tetrahedral.

Also, $\left[Ni\right(CO{)}_4{]}^{-2}$ has a hybridisation of $ds{p}^2$ and therefore its geometry is square planar.

Thus, $Ni(CO{)}_4$ and $Ni(CO{)}_4^{2-}$ both are tetrahedral in shape is a false statement.