Question

Statement-I: Alkali metals dissolve in liquid ammonia to give blue solutions
Statement-II: Alkali metals in liquid ammonia give solvated species of the type $\left[M\right(N{H}_3{)}_n{]}^{+}$ (M = alkali metals)

• A. Statement-I is true; Statement-II is true; Statement-II is the correct explanation for Statement-I
• B. Statement-I is true; Statement-II is true; Statement-II is not the correct explanation for Statement-I
• C. Statement-I is true; Statement-II is false
• D. Statement-I is false; Statement-II is true

Answer 1

The correct option is B Statement-I is true; Statement-II is true; Statement-II is not the correct explanation for Statement-I

The alkali metals dissolve in liquid ammonia without the evolution of hydrogen. The color of the dilute solutions is blue.
$N{a}^{+}+(x+y)N{H}_3\to \left[Na\right(NH3{)}_x{]}^{+}+\underset{Ammoniatedelectrons}{\left[e\right(N{H}_3{)}_y{]}^{-}}$
On heating, its blue color changes to bronze. It is an ammoniated electron which is responsible . for the color and other properties,but not solvated species of the type $\left[M\right(N{H}_3{)}_n{]}^{+}$ (M = alkali metals). The solutions are good conductors of electricity and have strong reducing properties. The solutions are paramagnetic in nature.
So Statement-I is true; Statement-II is true; Statement-II is not the correct explanation for Statement-I
Hence option B is correct.