Statement I: An element $(X)$ with an atomic number of 16 has 14 electrons in $X^{2 -}$ .
Statement II: Two protons bind the two outermost electrons.

Statement 1 and Statement 2 are correct and Statement 2 is the correct explanation of Statement 1

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Both the Statement 1 and Statement 2 are correct and Statement 2 is NOT the correct explanation of Statement 1

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Statement 1 is correct but Statement 2 is not correct

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Statement 1 is not correct but Statement 2 is correct

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Both the Statement 1 and Statement 2 are not correct

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Solution

The correct option is C Both the Statement 1 and Statement 2 are not correct
Option $E$ is the correct answer.
Both the statements are incorrect. An element with atomic number 16 when has 14 electrons forms $X^{2 +}$
These 14 electrons can be written has (2,8,4). Thus there are 4 electrons in the outermost orbit. There are 4 outermost electrons.

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Statement I: An element (X) with an atomic number of 16 has 14 electrons in X2−.Statement II: Two protons bind the two outermost electrons.

Statement I: An element $(X)$ with an atomic number of 16 has 14 electrons in $X^{2 -}$ .
Statement II: Two protons bind the two outermost electrons.