Question

Statement I: Aniline on reaction with $NaN{O}_2/HCl$ at $0^{o}C$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate.
Statement II: The colour of the compound formed in the reaction of aniline with $NaN{O}_2/HCl$ at $0^{o}C$ followed by coupling with $\beta$-naphthol.

• A. Statement I and statement II are true and statement II is the correct explanation of statement I
• B. Statement I and statement II are true and statement II is not the correct explanation of statement I
  
• C. Statement I is true and the statement II is false
• D. Statement I is false and the statement II is true
  

Answer 1

Answer: (D)

Statement I is false and the statement II is true

Statement I: Aniline on reaction with $NaN{O}_2/HCl$ at $0^{o}C$ followed by coupling with β-naphthol gives scarlet red coloured dye. Aniline on reaction with $NaN{O}_2/HCl$ forms a diazonium salt. This diazonium salt is then coupled with β-naphthol.
Statement II: The colour obtained is the colour of the compound formed in the reaction of aniline with $NaN{O}_2/HCl$ at $0^{o}C$ followed by coupling with β-naphthol.

Hence, statement I is false and the statement II is true.