Question

Statement I : $H_{2}S{O}_4$ is not used during the reaction of alcohols with $KI$.
Statement II : $H_{2}S{O}_4$ oxidises $KI$ to $I_2$ and will prevent reaction of alcohol with $KI$.

• A. Statement I & Statement II are correct and statement II is correct explanation of statement I
• B. Statement I & Statement II are correct and statement II is not correct explanation of statement I
• C. Statement I is correct and Statement II is wrong
• D. Statement I is wrong and Statement II is correct

Answer 1

The correct option is A Statement I & Statement II are correct and statement II is correct explanation of statement I

$H_{2}S{O}_4$ is not used during the reaction of alcohols with KI due to following reactions:

$KI$ oxidised by sulphuric acid and iodine gas forms.
$8KI+5H_{2}S{O}_4\to 4K_{2}S{O}_4+4I_2+H_{2}S+4H_{2}O$.