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Question

Statement-I : If roots of the equation x2−bx+c=0 are two consecutive integers, then b2−4c=1.
Statement-II : If a,b,c are odd integers, then the roots of the equation 4abcx2+(b2−4ac)x−b=0 are real and distinct.

A
Statement-I is true, Statement-II is true ; Statement-II is correct explanation for Statement-I
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B
Statement-I is true, Statement-II is true ; Statement-II is NOT a correct explanation for statement-I
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C
Statement-I is true, Statement-II is false
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D
Statement-I is false, Statement-II is true
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Solution

The correct option is B Statement-I is true, Statement-II is true ; Statement-II is NOT a correct explanation for statement-I
If roots of the equation x2bx+c=0 are two consecutive integers.
Difference between roots is 1.
Δa=1
b24c=1
4abcx2+(b24ac)xb=0
Δ=(b24ac)2+164ab2c=(b2+4ac)2>0 (a,b,c are odd integers.)
Roots are real and distinct.
Statement-I is true, Statement-II is true ; Statement-II is NOT a correct explanation for statement-I
Hence, option B.

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