Question

Statement-I : If roots of the equation $$x^2- bx + c = 0$$ are two consecutive integers, then $$b^2- 4c = 1$$.Statement-II : If $$a, b, c$$ are odd integers, then the roots of the equation $$4abcx^2 + (b^2- 4ac)x- b = 0$$ are real and distinct.

A
Statement-I is true, Statement-II is true ; Statement-II is correct explanation for Statement-I
B
Statement-I is true, Statement-II is true ; Statement-II is NOT a correct explanation for statement-I
C
Statement-I is true, Statement-II is false
D
Statement-I is false, Statement-II is true

Solution

The correct option is B Statement-I is true, Statement-II is true ; Statement-II is NOT a correct explanation for statement-IIf roots of the equation $$x^2-bx+c=0$$ are two consecutive integers.$$\Rightarrow$$ Difference between roots is $$1$$.$$\Rightarrow \displaystyle\frac{\sqrt{\Delta}}{a}=1$$$$\therefore b^2-4c=1$$$$4abc x^2+(b^2-4ac)x-b=0$$$$\Delta = (b^2-4ac)^2+164ab^2c=(b^2+4ac)^2>0$$  ($$\because a,b,c$$ are odd integers.)$$\therefore$$ Roots are real and distinct.Statement-I is true, Statement-II is true ; Statement-II is NOT a correct explanation for statement-IHence, option B.Mathematics

Suggest Corrections

0

Similar questions
View More