Statement I: The $A l^{3 +}$ ion needs to be reduced to form aluminum metal.
Statement II: Reduction is a gain of electrons.

Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.

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Both Statement I and Statement II are correct, but Statement II is not the correct explanation of Statement I.

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Statement I is correct, but Statement II is incorrect.

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Statement I is incorrect, but Statement II is correct.

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Solution

The correct option is A Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.
Option A is the correct answer.
Aluminium metal can be written as $A l$ , whereas, Aluminium ion is written as ${A l}^{3 +}$ . ${A l}^{3 +}$ has three electrons lesser than $A l$ . To convert ${A l}^{3 +}$ to $A l$ , we need to reduce this cation by adding three more electrons.
Because, reduction is a gain of electrons, we need to add three more electrons to ${A l}^{3 +}$ cation to convert it into $A l$ .

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Statement I: The Al3+ ion needs to be reduced to form aluminum metal.Statement II: Reduction is a gain of electrons.

Statement I: The $A l^{3 +}$ ion needs to be reduced to form aluminum metal.
Statement II: Reduction is a gain of electrons.