Statement I: The fluoride ion has a larger radius than the fluorine atom.
Statement II: The fluoride ion has $8$ electrons and $9$ protons.

Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I.

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Both Statement I and Statement II are correct, but Statement II is not the correct explanation of Statement I.

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Statement I is correct, but Statement II is incorrect.

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Statement I is incorrect, but Statement II is correct.

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Solution

The correct option is C Statement I is correct, but Statement II is incorrect.
Option A is the correct answer.
Fluorine atom has 9 electrons in its orbit which can be written as (2,7). When it is converted to a Fluoride ion its electronic configuration can be written as (2,8). As the number of electrons in its outermost orbit is increased, the nuclear force of attraction on each electron is thus decreased. Thus the radius of Fluoride ion is larger than the Fluorine atom. In general, anions have a larger radius than their corresponding atoms.
Fluorine atom can be converted to Fluoride ion by increasing its number of electrons by one. Thus Fluoride ion has 9 electrons and 9 protons.
Hence statement 1 is true but statement 2 is false.

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Statement I: The fluoride ion has a larger radius than the fluorine atom.Statement II: The fluoride ion has 8 electrons and 9 protons.

Statement I: The fluoride ion has a larger radius than the fluorine atom.
Statement II: The fluoride ion has $8$ electrons and $9$ protons.