Statement - I: The mixing of two completely miscible liquid. A and B showing positive deviation from Raoult’s law is followed by an absorption of heat
Statement - II: The A- B molecular interaction forces are stronger than the A-A or B-B molecular interaction forces.

Statement - I is true, Statement - 2 is true; Statement - 2 is a correct explanation for Statement - I

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Statement - I is true, Statement - 2 is true; Statement - 2 is not a correct explanation for Statement - I

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Statement - I is true, Statement - 2 is false

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Statement - I is false, Statement - 2 is true

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Solution

The correct option is C Statement - I is true, Statement - 2 is false
For a mixture showing positive deviation from raoults law,
$Δ H > 0 a n d Δ V > 0$
because the interaction forces between the solute and the solvent become weak.

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Statement - I: The mixing of two completely miscible liquid. A and B showing positive deviation from Raoult’s law is followed by an absorption of heatStatement - II: The A- B molecular interaction forces are stronger than the A-A or B-B molecular interaction forces.

The correct option is C Statement - I is true, Statement - 2 is falseFor a mixture showing positive deviation from raoults law,ΔH>0andΔV>0because the interaction forces between the solute and the solvent become weak.

Statement - I: The mixing of two completely miscible liquid. A and B showing positive deviation from Raoult’s law is followed by an absorption of heat
Statement - II: The A- B molecular interaction forces are stronger than the A-A or B-B molecular interaction forces.

The correct option is C Statement - I is true, Statement - 2 is false
For a mixture showing positive deviation from raoults law,
$Δ H > 0 a n d Δ V > 0$
because the interaction forces between the solute and the solvent become weak.