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Question

Statement - I :

Two blocks of masses m and M are placed on a horizontal surface. The coefficient of friction between two blocks is μ1 and that between the block M and horizontal surface is μ2. The maximum force that can be applied to block M so that the two blocks move without slipping is F=(μ1+μ2)(M+m)g

Statement - II:
F=Total maximum acceleration

A
Statement1 is True, Statement2 is True; Statement2 is a correct explanation for Statement1
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B
Statement1 is True, Statement2 is True; Statement2 is NOT a correct explanation for Statement1
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C
Statement1 is True, Statement2 is False
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D
Statement1 is False, Statement2 is True
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Solution

The correct option is C Statement1 is True, Statement2 is False
Friction between m and M,f=μ1mg and between M and surface, f=μ2(M+m)g
For system to have acceleration a net force
F=(M+m)a+μ2(M+m)g
Acceleration of mass m,a=μ1mgm=μ1g
F=μ1(M+m)g+μ2(M+m)g
=(μ1+μ2)(M+m)g

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