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Question

Statement-I : a×(b×c),b×(c×a),c×(a×b) are coplanar vectors.

Statement-II: If there exists scalars l, m, n not all zero such that la+mb+nc=0, then the vectors a,b, c are coplanar

A
Both I and II are true and II is the correct explanation of I
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B
Both I and II are true but II is not correct explanation of I.
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C
I is true, II is false
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D
I is false, II is true
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Solution

The correct option is C Both I and II are true and II is the correct explanation of I
When we look at statement 2, l¯¯¯a+m¯¯b+n¯¯c=0 implies any of the three vectors ¯¯¯a,¯¯b or ¯¯c can be written in terms of the remaining two vectors.
Thus, the vectors become coplanar and hence statement 2 is true.
¯¯¯a×(¯¯bׯ¯c)=(¯¯¯a.¯¯c)¯¯b(¯¯¯a.¯¯b)¯¯c
¯¯b×(¯¯cׯ¯¯a)=(¯¯b.¯¯¯a)¯¯c(¯¯b.¯¯c)¯¯¯a
¯¯c×(¯¯¯aׯ¯b)=(¯¯c.¯¯b)¯¯¯a(¯¯c.¯¯¯a)¯¯b
Since dot product is commutative, when we add the three relations, we get
¯¯¯a×(¯¯bׯ¯c)+¯¯b×(¯¯cׯ¯¯a)+¯¯c×(¯¯¯aׯ¯b)
=(¯¯¯a¯¯c)¯¯b(¯¯¯a¯¯b)¯¯c+(¯¯¯a.¯¯b)¯¯c(¯¯b.¯¯c)¯¯¯a+(¯¯b¯¯c)¯¯¯a(¯¯¯a¯¯c)¯¯b
=0
Therefore the vectors ¯¯¯a×(¯¯bׯ¯c),¯¯b×(¯¯cׯ¯¯a),¯¯c×(¯¯¯aׯ¯b) are coplanar and thus it becomes similar to the explanation provided in statement 2.
Hence, both I and II are correct and II is the correct explanation of I.

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