wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Statement-l: nr=0(r+1)nCr=(n+2)2n1
Statement-2: nr=0(r+1)nCrxr=(1+x)n+nx(1+x)n1

A
Statement-1 is true, Statement-2 is true; Statement -2 is not a correct explanation for Statement-1.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Statement-1 is true, Statement-2 is false.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Statement-1 is false, Statement-2 is true.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.
nr=0(r+1)nCrxr=nr=0r.Crxr+nr=0Cr.x=nxnr=1Cr1x+nr=0Crx=nx(1+x)n1+(1+x)n ... (i)
Statement-2 is true.
Putting x=1 in (i), we get nr=0(r+1)nCr=(n+2).2n1 Statement-l is also true and followed by I.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Logarithmic Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon