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Properties of Methane

Statement: On...

Question

$S t a t e m e n t$ : One mole of propyne reacts with sodium in presence of liquid ammonia to produce propane.
If the given statement is true then enter 1, if false enter 0.

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Solution

The reduction of propyne with sodium in liquid ammonia gives prop-1-ene.
Here, the carbon-carbon triple bond is reduced to the double bond.
Hence, the given statement is $f a l s e$ and the correct entry is $0$ .

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