Question

Statement: The oxidation number of carbon in $NaCNS$ is $+4$

State whether the given statement is true or false.

• A. True
• B. False
• C. Anomalous
  
• D. None of these

Answer 1

Answer: (A)

True

Let $x$ be the oxidation number of C in $NaCNS$.
Since the overall
charge on the complex is $0$, the sum of oxidation states of all elements in
it should be equal to $0$.
Therefore, $x+1+(-2)+(-3)=0$
or, $x=+4$
Hence, the oxidation number of carbon in $NaCNS$ is $+4$.

Hence, the given statement is $\text{true}$