Question

Statement: Total millimoles of $Se{O}_3^{2-}$ = Total millimoles of $Br{O}_3^{⊝}-$ millimoles of $Br{O}_3^{⊝}$ (excess) in reaction (ii)

• A. True
• B. False

Answer 1

The correct option is B False

The difference in the total millimoles of $Br{O}_3^{-}$ and millimoles of excess $Br{O}_3^{-}$ corresponds to millimoles of $Br{O}_3^{-}$ that reacts with $Se{O}_3^{2-}$.

But the $n$-factor for $Se{O}_3^{2-}$ is 2 and the $n$-factor for $Br{O}_3^{-}$ is $5$.

Since the $n$-factors are different, the number of millimoles of $Se{O}_3^{2-}$ will not be equal to the difference in the total millimoles of $Br{O}_3^{-}$ and millimoles of excess $Br{O}_3^{-}$.

Hence, the given statement is $\text{false}$.

The true statement will be the number of meq. of $Se{O}_3^{2-}$ will be equal to the difference in the total meq. of $Br{O}_3^{-}$ and meq. of excess $Br{O}_3^{-}$ .