The correct option is E Only conclusion I is true
Conclusion I. x≥V→As E=U ∵U≤X∴ E≤X and V≤E ⇒X≥VSo, conclusion I is true.Conclusion II. E>A→As E≤X and X>A
∴ X is greater than both E and X and it can't be determined that E is smaller than or greater than A. Thus, conclusion II is false.