Statement1: $c o s e c^{2} A$ - $c o t^{2} A$ = 1

Statement2: 1 + $t a n^{2} A$ = $s e c^{2} A$

Both statements are false.

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Statement 1 is true and Statement 2 is false.

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Both statements are true.

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Statement 1 is false and Statement 2 is true.

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Solution

The correct option is C
Both statements are true.

Identity : 1 + $c o t^{2} A$ = $c o s e c^{2} A$

Identity : 1 + $t a n^{2} A$ = $s e c^{2} A$

Hence, the both the statements are true.

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Similar questions

Statement1 : $c o s^{2} A$ + $s i n^{2} A$ = 1

Statement2 : $s e c^{2} A$ + $t a n^{2} A$ = 1

\frac{{tan}^{2} A}{{tan}^{2} A + 1} + \frac{c o s e c^{2} A}{{sec}^{2} A + c o s e c^{2} A} = 1

\frac{1 - {t a n}^{2} A}{{c o t}^{2} A - 1} = {t a n}^{2} A

\frac{1 + t a n^{2} A}{1 + c o t^{2} A}

t a n^{2} A .

c o s e c^{2} A - c o t^{2} A

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