Question

Staten whether the statement is True/False

The value of the $\underset{x\to 1}{lim}{(1+{\log }_{e}x)}^{1/1-x}$ is equal to $e$

• A. True
• B. False

Answer 1

The correct option is B False

Given,

${lim}_{x\to 1}{(1+{\log }_{e}x)}^{\frac{1}{1-x}}$

$={(1+{\log }_{e}1)}^{\frac{1}{1-1}}$

$=(1+0{)}^0$

$=0$

Hence the given statement is wrong.