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Question

Steam at 100C is passed into 1.1kg of water contained in a calorimeter of water equivalent 0.02kg at 15C till the temperature of the calorimeter and its contents reaches 80C. Considering the latent heat of steam =540calg1 and specific heat capacity of water =4183Jkg1K1 or =1calkg1K1,
calculate the mass of the steam condensed.


A

0.139

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B

0.065

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C

0.263

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D

0.144

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Solution

The correct option is A

0.139


Given:
Mass of water and calorimeter =1.10+0.02=1.12kg
Specific heat capacity of water =4.184×103Jkg1K1=1calkg1K1
Let the mass of steam=mkg
Latent heat of vaporization of water at 100C=540calg1

We know that,
Heat lost by steam=Heat gained by water+calorimeter

or, mL+mc(10080)=1.2×c×(8015)
where, m is the mass of the steam, L is the latent heat of vaporization and c is the specific heat of water.
or, m[540+(1×20)]=1.2×1×65
or, m=1.2×1×65560=72.8560kg
or, m=0.139kg


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