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Question

Steam enters in adiabatic turbine with enthalpy 3000 kJ/kg at a steady flow rate of 8 kg/s. At a point where enthalpy is 2820 kJ/kg, 3 kg/s is extracted. The remaining mass further expands till enthalpy becomes 2200 kJ/kg. The power developed by the turbine is

A
3.5 MW
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B
4 MW
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C
4.5 MW
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D
5 MW
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Solution

The correct option is C 4.5 MW

WT=8(h1h2)+(83)(h2h3)


=8(30002820)+5(28202200)

=4540 kW=4.544.5 kW


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