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Question

Steam is passed into 22 gm of water at 20oC. The mass of water that will be present when the water acquires a temperature of 90^oC (latent heat of steam is 540 cal/gm) is

A
24.8 gm
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B
24 gm
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C
36.6 gm
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D
30 gm
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Solution

The correct option is A 24.8 gm
Solution:
mLS+msω(10090)=22Sω(9020)
m×540+m×1×10=22×70
m=22×70550=2.8g
Total mass of water =22+2.8=24.8g


Hence A is the correct option

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