Question

steam is passed through 2.2 kg of water at 20C. the mass of water that will be present when the water acquires a temperature of 90C is? latent heat of steam is 2.27*10^6

Answer 1

Dear Student,
$$\begin{gathered} Takenheat=givenheat \\ 2.2\times 4200\times (90-20)=m\times 2.27\times {10}^6+m\times 4200\times (100-90) \\ 22\times 4200\times 70=m\times 2.27\times {10}^6+m\times 4.2\times {10}^4 \\ 6.46\times {10}^5=m\times (2.27+0.042)\times {10}^6 \\ m=\frac{6.46}{23.12}=279.4g \end{gathered}$$
Regards