Steam undergoes decomposition at high temperature as per the reaction H2Og - H2g-1-2O2g- - H-200 kJ mol-1- S-40 J mol-1The temperature at which equilibrium constant is unit is -

The correct option is B 5000 Kelvin Δ G^∘=Δ H^∘ TΔ S^∘= RT nbsp; ln Keq = 0 nbsp;[Keq = 1] . ⇒ T=Δ H^∘/Δ S^∘=200× 10^3/40=5000 nbsp; K ...

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Steam undergo...

Question

Steam undergoes decomposition at high temperature as per the reaction
$H_{2} O (g) ⇌ H_{2} (g) + \frac{1}{2} O_{2} (g), Δ H^{\circ} = 200 k J m o l^{- 1} Δ S^{\circ} = 40 J m o l^{- 1}$
The temperature at which equilibrium constant is unit is :

3000 Kelvin

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5000 Kelvin

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5333 Kelvin

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5 Kelvin

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Δ H

C (s) + \frac{1}{2} O_{2} (g) \to C O (g)

Δ H = - 110 k J

C (s) + H_{2} O (g) \to C O (g) + H_{2} (g)

Δ H = 132 k J

Δ H

C (s) + \frac{1}{2} O_{2} (g) \to C O (g);

Δ H = - 110 k J

C (s) + H_{2} O (g) \to C O (g) + H_{2} (g);

Δ H = 132 k J

H_{2} O (g) ⇌ H_{2} (g) + \frac{1}{2} O_{2} (g)

α =

P =

Δ H

C (s) + 1 / 2 O_{2} (g) \to C O (g); Δ H = - 110

C (s) + H_{2} O (g) \to C O (g) + H_{2} (g); Δ H = 132

Δ H

C_{(} s) + \frac{1}{2} O_{2} (g) \to C O (g)

Δ H = - 110 k J

C (s) + H_{2} O (g) \to C O (g) + H_{2} (g)

Δ = 132 k J

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