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Question

Stearic acid [CH3(CH2)16CO2H] is a fatty acid, the part of fat that stores most of the energy. 1.0 g of stearic acid was burned in a bomb calorimeter. The bomb had a heat capacity of 652 J/C. If the temperature of 500 g water (c=4,18 J/gC) rose from 25.0 to 39.3C, how much heat was released when the stearic acid was burned? [Given CP(H2O)=4.18 J/gC].

A
39.21 kJ
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B
29.91 kJ
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C
108 kJ
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D
9.32 kJ
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Solution

The correct option is A 39.21 kJ
As energy is conserved
Heat released = (heat capacity of bomb)ΔT + mwCpΔT
mw is a mass of water in the bomb calorimeter
By taking values from the question ΔT
=14.3
H =652×14.3+500×4.18×14.3
=39210.6J
The heat released when the stearic acid was burned
=39.21kJ

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