Step 2. Draw an arc with radius r and B as centre on the first arc at C. So, $∠ C O A$ is __.
Note: Answer in degrees.

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Solution

Statement: Draw an arc with radius r and B as centre on the first arc at C. So, $∠ C O A$ is $120^{\circ}$ .
Reason: As explained above, by cutting the circumference of a circle by an arc of equal radius the angle formed at the centre of the circle is $60^{\circ}$ . The angle formed by repeating the step twice will be $2 \times 60^{\circ} = 120^{\circ}$ . So, $∠ C O A$ is $120^{\circ}$ .

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Step 3: With r as radius, draw arcs with B and C as centres. The point of intersection of the arcs is point D. $∠ D O A$ is__
Note: Answer in degrees.

Step 5. Draw 2 arcs with centres A and B respectively with radius R. If the arcs intersect at H, value of $∠ H O A$ is __.
Note: Answer in degrees.

If I do the following constructions step by step, what will be the angles constructed (in degrees)?

Step 1. Draw an arc on the line XY with an arbitrary point O on line XY, as centre and radius r. With the same radius and point of intersection of arc and line, ‘A’, as centre draw another arc on the first arc at point B. So, $∠ A O B$ is __.

Step 4. Now, change the radius to R. Draw an arc such that it intersects line XY at E and line OD at F. Draw arcs with radius R and centres at E and F respectively such that they intersect at G. The $∠ G O E$ is __.
Note: Answer in degrees.

Q. Steps for the construction of a 90° angle.

Choose the correct order.

1: Draw a ray OA.

2: With C and D as centres and radius more than half of CD, draw two arcs cutting each other at E. Join OE.

3: With O as centre and any convenient radius, draw an arc cutting OA at B.

4: With B as centre and the same radius, draw an cutting the first arc at C.

5: With C as centre and the same radius, draw an arc cutting again the first arc at D.

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Step 2. Draw an arc with radius r and B as centre on the first arc at C. So, ∠COA is __. Note: Answer in degrees.

Step 2. Draw an arc with radius r and B as centre on the first arc at C. So, $∠ C O A$ is __.
Note: Answer in degrees.