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Construction an Equilateral Triangle of Given Height

Steps for the...

Question

Steps for the construction of an equilateral triangle of height 3.2cm is given below. Choose the correct order.

1.Draw a line segment XY
2.Take any point M on XY. Draw ZM $⊥$ XY
3.With M as centre and radius 3.2cm ,draw an arc ,cutting MZ at A.
4.Construct $∠ M A B = 30^{\circ}$ and $∠ M A C = 30^{\circ}$ ,with B and C on XY.

2,1,3,4

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1,2,4,3

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1,2,3,4

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2,1,4,3

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Solution

The correct option is C 1,2,3,4
Steps for the construction of an equilateral triangle of height 3.2cm is given below. Choose the correct order.

1.Draw a line segment XY
2.Take any point M on XY. Draw ZM $⊥$ XY
3.With M as centre and radius 3.2cm ,draw an arc ,cutting MZ at A.
4.Construct $∠ M A B = 30^{\circ}$ and $∠ M A C = 30^{\circ}$ ,with B and C on XY.

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Similar questions

⊥

80^{\circ}

∠ M A B = \frac{80}{2} = 40^{\circ}

∠ M A C = \frac{80}{2} = 40^{\circ}

⊥

∠ M = 90^{\circ}

∠ N M P = 90^{\circ}

The steps to construct $60^{\circ}$ angle is given below. Arrange these steps in the correct sequence.

1. Taking O as centre, draw an arc of any size to cut OA at B.

2. Draw a line segment OA of any suitable length.

3. Join OC and produce it to any point D.

4. With B as centre draw another arc of the same size to cut the previous arc at C.

∠ Q = 60^{\circ}

∠ M Q R = 60^{\circ}

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