Question

Steve went to Pitt street for buying clothes. The cost of 5 jeans is $x$ whereas the cost of $8$ shirts is $y$. How much money he spent on buying $4$ jeans and $3$ shirts?

• A. $\frac{4x}{5}+\frac{5y}{8}$
• B. $\frac{4x}{7}+\frac{3y}{8}$
• C. $\frac{4x}{5}+\frac{3y}{8}$
• D. $\frac{3x}{5}+\frac{3y}{8}$

Answer 1

The correct option is C $\frac{4x}{5}+\frac{3y}{8}$

Given:
Cost of $5$ jeans is $x$.

And cost of $8$ shirts is $y$.

So, the cost of $1$ jeans = $\frac{x}{5}$

And the cost of $1$ shirt = $\frac{y}{8}$

Steve bought $4$ jeans and $3$ shirts.

Cost of $4$ jeans = $4$ $\times$ cost of $1$ jeans = $4\times \frac{x}{5}=\frac{4x}{5}\cdots \left(1\right)$

Similarly, the cost of $3$ shirts = $3\times$ cost of $1$ shirt = $3\times \frac{y}{8}=\frac{3y}{8}\cdots \left(2\right)$

From $\left(1\right)$ and $\left(2\right)$,

The cost of $4$ jeans and $3$ shirts = cost of $4$ jeans + cost of $3$ shirts

So, the cost of $4$ jeans and $3$ shirts = $\frac{4x}{5}+\frac{3y}{8}$

$\therefore$ Steve would have spent $\frac{4x}{5}+\frac{3y}{8}$ money on buying $4$ jeans and $3$ shirts.