CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Stone drops from the edge of the roof. It passes window 2m high in 0.1 sec. How far is the roof above the top of the window? (takeg=10m/s2)

Open in App
Solution

Height of the window (h) = 2m
Acceleration due to gravity g=10 m/s2
Time taken (t) = 0.1 s
The velocity of the stone when it reaches the top of the window is to be calculated.
Applying the second equation of motion,
h=ut+12at2
2=u(0.1)+5(0.01)
(0.1)u=1.95
U=19.5m/s
Thus, the velocity 19.5 m/s will be the final velocity as soon as the stone starts covering the distance between the roof and the upper edge of the window.
As stone starts from rest i.e., u = 0
v2u2=2gh
(19.5)20=20h
h=19.01m
Distance between the roof and upper edge of the window = 19.01 m.


flag
Suggest Corrections
thumbs-up
119
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon