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Question

Stopping distance of a moving vehicle is directly proportional to

A
square of the initial velocity.
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B
square of the initial acceleration.
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C
the initial velocity.
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D
the initial accleration.
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Solution

The correct option is A square of the initial velocity.
Let s be the distance travelled by the vehicle before it stops.
So, final velocity would be v=0, let say, initial velocity is u
Using equation of motion
v2u2=2as
02u2=2as
So, stopping distance s=u22a
Thus, stopping distance is proportional to the square of the initial velocity.

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