Stopping potential -V volts- is plotted against frequency of light used - Find work functioneV- h- 6-62- 10-34 J- s-

We know work = energy and also #160;Maximum Kinetic energy =hν×Φ ——(1)where h= Plank's constant =6.62× 10 ^ 34 Js ν =5× 10 ^ 14 Herts(from ...

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Standard XII

Physics

Stopping Potential vs Frequency

Stopping pote...

Question

Stopping potential [V volts] is plotted against frequency of light used $[ν]$ . Find work function(eV). $(h = 6.62 \times 10^{- 34} J \times s)$ .

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Solution

We know work = energy and also
Maximum Kinetic energy $= h ν \times Φ$ ------(1)
where h= Plank's constant $= 6.62 \times 10^{- 34} Js$
$ν = 5 \times 10^{14} Herts(from figure) eV = 1.6 \times 10^{- 19} J$
Putting the values in 1 we get
Work= energy $= 6.62 \times 10^{- 34} \times (5 \times 10^{14}) - 1.6 \times 10^{- 19} = 1.71 \times 10^{- 19} J$

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Stopping potential [V volts] is plotted against frequency of light used [ν]. Find work function(eV). (h=6.62×10−34J×s).

We know work = energy and also Maximum Kinetic energy=hν×Φ------(1)where h= Plank's constant=6.62×10−34 Jsν=5×1014Herts(from figure)eV=1.6×10−19JPutting the values in 1 we getWork= energy =6.62×10−34×(5×1014)−1.6×10−19=1.71×10−19J

Stopping potential [V volts] is plotted against frequency of light used $[ν]$ . Find work function(eV). $(h = 6.62 \times 10^{- 34} J \times s)$ .