Straight section PO of circuit lies along the x-axis from x - - a-2 to x - a-2 and carries a redy current- The magnitude to magnetic field due to the section PO at a point y - - a will be

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Two Parallel Currents

Straight sect...

Question

Straight section PO of circuit lies along the x-axis from $x = - \frac{a}{2} t o x = \frac{a}{2}$ and carries a redy current. The magnitude to magnetic field due to the section PO at a point $y = \pm$ a will be

Proportional to a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Proportional to

a^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Proportional to 1/a

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B Proportional to 1/a
Given
A wire lies on x axis form -a/2 to +a/2
Solution
Magnetic field of a wire on a point is
$B = \frac{μ_{0} * i}{2 a} (s i n θ_{1} + s i n θ_{2})$
So for any value of theta
B is proportional to 1/a
The correct option is C

Suggest Corrections

Similar questions

Q. A straight section

P Q

of a circuit lies along the

X

axis from

x = - a / 2

x = a / 2

and carries a steady current

I

.Then the magnetic field due to the

P Q

section at a distance

x = + a

will be:

Q. A long, straight wire carries a current

i

. Let

B_{1}

be the magnetic field at a point

P

at a distance

d

from the wire. Consider a section of length

l

of this wire such that the point

P

lies on a perpendicular bisector of the section. Let

B_{2}

be the magnetic field at this point due to this section only. Find the value of

d / l

so that

B_{2}

differs from

B_{1}

1 %

A wire carries a steady current of 2.4 A. A straight section of the wire is 0.75 m long and lies along the x axis within a uniform magnetic field, B = (1.6 k) T. If the current is in the + x direction, what is the magnetic force on that section of wire?

Q. A long, straight, hollow conductor (tube) carrying a current has two sections

A

and

C

of unequal cross sections joined by a conical section

B

. 1, 2 and 3 are points on a line parallel to the axis of the conductor. The magnetic fields at 1, 2 and 3 have magnitudes

B_{1}, B_{2}

and

B_{3}

. Then,

Q. The magnetic field at a point due to a current carrying conductor is directly proportional to:

Join BYJU'S Learning Program

Straight section PO of circuit lies along the x-axis from x=−a2tox=a2 and carries a redy current. The magnitude to magnetic field due to the section PO at a point y=± a will be

The correct option is B Proportional to 1/aGivenA wire lies on x axis form -a/2 to +a/2SolutionMagnetic field of a wire on a point isB=μ0∗i2a(sinθ1+sinθ2)So for any value of thetaB is proportional to 1/aThe correct option is C

Straight section PO of circuit lies along the x-axis from $x = - \frac{a}{2} t o x = \frac{a}{2}$ and carries a redy current. The magnitude to magnetic field due to the section PO at a point $y = \pm$ a will be

The correct option is B Proportional to 1/a
Given
A wire lies on x axis form -a/2 to +a/2
Solution
Magnetic field of a wire on a point is
$B = \frac{μ_{0} * i}{2 a} (s i n θ_{1} + s i n θ_{2})$
So for any value of theta
B is proportional to 1/a
The correct option is C