Strength in volumes of a solution containing $30.36 g / l i t r e$ of $H_{2} O_{2}$ is:

10

volume

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20

volume

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5

volume

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None of these

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Solution

The correct option is A $10$ volume
Gram equivalents of $H_{2} O_{2} = \frac{m a s s o f H_{2} O_{2}}{e q u i v a l e n t m a s s o f H_{2} O_{2}} = \frac{30.36}{17} = 1.786$

$N o r m a l i t y = \frac{g r a m e q u i v a l e n t s o f H_{2} O_{2}}{v o l u m e o f s o l u t i o n} = \frac{1.786}{1} = 1.786 N$

$V o l u m e s t r e n g t h o f H_{2} O_{2} = 5.6 \times n o r m a l i t y = 5.6 \times 1.786$

$= 10 v o l u m e$

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